25. banyak mobil = x banyak motor = y .. x + y = 75 ....(1) 4x + 2y = 210 atau 2x + y = 105 ..(2) . x + y = 75 2x + y = 105 .....................(-) -x = - 30 x = 30 y = 75 - 30 y = 45
pendapatan parkir (x,y) --> P = 4.000x + 2.000 y (rupiah) (30, 45) --> P = 30(4.000) + 45(2.000) P = 120.000 + 90.000 P = 210.000
maaf kalau salah
Panjang busur AB = 135/360 x keliling lingkaran
(AB) = 3/8 x 2 x 22/7 x 21
(AB) = 49,5
24. <COD = 44
<AOD +<COD = 180 ( berpelurus)
<AOD = 180 - < COD
<AOD= 180 - 44
<AOD = 136
<ABD = (1/2 )(136)
<ABD = 68
25.
banyak mobil = x
banyak motor = y
..
x + y = 75 ....(1)
4x + 2y = 210 atau 2x + y = 105 ..(2)
.
x + y = 75
2x + y = 105
.....................(-)
-x = - 30
x = 30
y = 75 - 30
y = 45
pendapatan parkir (x,y) --> P = 4.000x + 2.000 y (rupiah)
(30, 45) --> P = 30(4.000) + 45(2.000)
P = 120.000 + 90.000
P = 210.000