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Verified answer
Jawabᵃlog b + ᵇlog a⁴ + 4 = 0
ᵃlog b + 4 (ᵇlog a) + 4 = 0
misalkan
ᵃlog b = x → ᵇlog a = 1/x
x + 4 (1/x) + 4 = 0 ....}kalikan x
x² + 4 + 4x = 0
x² + 4x + 4 = 0
(x + 2)² = 0
x = - 2
ᵃlog b = - 2 → a⁻² = b → a² = (1/b)
nilai dari
a² b - ᵃlog b = (1/b)(b) - (-2)
= 1 + 2
= 3