1. f ( x ) = x² - 7x + 12
persamaan sumbu simetri
xp = - b/2a = - (- 7)/2( 1 ) = 7/2 = 3½ ✔
2. nilai maksimum /minimum f
substitusi xp = 3½ ke persamaan f ( x )
(7/2²) - 7 7/2 + 12
= 49/4 - 49/2 +12
= 49/4 - 98/4 + 48/4
= -¼ ✔
3. Koordinat titik balik ( xp ,yp)
(7/2 , -¼) ✔
4.Titik patung dengan sumbu x maka f ( x ) = 0
x² - 7x + 12 = 0
( x - 4 ) ( x - 3 ) = 0
x = 4 u k = 3
Jadi titik potongnya ( 4 ,0) , ( 3 , 0 )✔
╔✨✨ ══════╗*
*❄️ ing ing❄️*
*╚══════ ✔️✔️╝*
Pembahasan :
1. Diketahui f ( x ) = x² - 7x + 12
xp = - b/2a = - (- 7)/2( 1 ) = 7/2 = 3 1/2
substitusi xp = 3 1/2ke persamaan f ( x )
= -¼
Maaf saya bantu semampuku ya kk hanya 2 soal.
Semoga bermanfaat.
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1. f ( x ) = x² - 7x + 12
persamaan sumbu simetri
xp = - b/2a = - (- 7)/2( 1 ) = 7/2 = 3½ ✔
2. nilai maksimum /minimum f
substitusi xp = 3½ ke persamaan f ( x )
(7/2²) - 7 7/2 + 12
= 49/4 - 49/2 +12
= 49/4 - 98/4 + 48/4
= -¼ ✔
3. Koordinat titik balik ( xp ,yp)
(7/2 , -¼) ✔
4.Titik patung dengan sumbu x maka f ( x ) = 0
x² - 7x + 12 = 0
( x - 4 ) ( x - 3 ) = 0
x = 4 u k = 3
Jadi titik potongnya ( 4 ,0) , ( 3 , 0 )✔
╔✨✨ ══════╗*
*❄️ ing ing❄️*
*╚══════ ✔️✔️╝*
Pembahasan :
1. Diketahui f ( x ) = x² - 7x + 12
persamaan sumbu simetri
xp = - b/2a = - (- 7)/2( 1 ) = 7/2 = 3 1/2
2. nilai maksimum /minimum f
substitusi xp = 3 1/2ke persamaan f ( x )
(7/2²) - 7 7/2 + 12
= 49/4 - 49/2 +12
= 49/4 - 98/4 + 48/4
= -¼
Maaf saya bantu semampuku ya kk hanya 2 soal.
Semoga bermanfaat.