[tex]A = (csc \: 45°) {}^{csc \: 30°} + tg45° \\ A = ( \sqrt{2} ) {}^{2} + 1 \\ A = 2 + 1 \\ \boxed{A = 3}[/tex]
[tex]P = 5sen \: 53° - 5sen \: 37° \\ P = 5 \times \frac{4}{5} - 5 \times \frac{3}{5} \\ P = 4 - 3 \\ \boxed{P = 1}[/tex]
[tex]→ \boxed{ A {}^{P} = {3}^{1} = 3}[/tex]
[tex]→ \boxed{Altura = x + y}[/tex]
[tex]x = 60 \: cm \times tan \: 37° \\ x = 60 \: cm \times \frac{3}{4} \\ \boxed{x = 45 \: cm}[/tex]
[tex]y = 60 \: cm \times tan \: 53° \\ y = 60 \: cm \times \frac{4}{3} \\ \boxed{y = 80 \: cm}[/tex]
[tex]Altura = x + y \\ Altura = 45 \: cm + 80 \: cm \\ → \boxed{Altura = 125 \: cm}[/tex]
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☆ PROBLEMA 1
[tex]A = (csc \: 45°) {}^{csc \: 30°} + tg45° \\ A = ( \sqrt{2} ) {}^{2} + 1 \\ A = 2 + 1 \\ \boxed{A = 3}[/tex]
[tex]P = 5sen \: 53° - 5sen \: 37° \\ P = 5 \times \frac{4}{5} - 5 \times \frac{3}{5} \\ P = 4 - 3 \\ \boxed{P = 1}[/tex]
[tex]→ \boxed{ A {}^{P} = {3}^{1} = 3}[/tex]
☆ RESPUESTA:
[tex]∴ \boxed{A) \: 3}[/tex]
☆ PROBLEMA 2
[tex]→ \boxed{Altura = x + y}[/tex]
[tex]x = 60 \: cm \times tan \: 37° \\ x = 60 \: cm \times \frac{3}{4} \\ \boxed{x = 45 \: cm}[/tex]
[tex]y = 60 \: cm \times tan \: 53° \\ y = 60 \: cm \times \frac{4}{3} \\ \boxed{y = 80 \: cm}[/tex]
[tex]Altura = x + y \\ Altura = 45 \: cm + 80 \: cm \\ → \boxed{Altura = 125 \: cm}[/tex]
☆ RESPUESTA:
[tex]∴ \boxed{C) \: 125 \: cm}[/tex]