Materi : Barisan dan Geometri
Pola barisan aritmatika [ apel ]
8, 12, 16, 20, ...
Suku Pertama = 8 , Beda = 4
Maka rumus pola : Un = 4n + 4
Pola barisan bertingkat [ jeruk ]
1, 4, 9, ... [ a = 1 ]
+3, +5, ... [ b = 3 ]
+2, ... [ c = 2 ]
Maka rumus pola :
Un = a + b( n - 1 ) + c/2( n - 1 )( n - 2 )
Un = 1 + 3( n - 1 ) + 2/2( n² - 3n + 2 )
Un = 1 + 3n - 3 + n² - 3n + 2
Un = n² + 3n - 3n + 3 - 3
Un = n²
n² = Un
n² = 169
n = √169
n = 13 [ suku ke - 13 ]
---
Un = 4n + 4
U13 = 4(13) + 4
U13 = 52 + 4
U13 = 56 pohon apel { c. }
Semoga bisa membantu
[tex] \boxed{ \colorbox{navy}{ \sf{ \color{lightblue}{ Answer\:by\: BLUEBRAXGEOMETRY}}}} [/tex]
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Verified answer
Materi : Barisan dan Geometri
Pola barisan aritmatika [ apel ]
8, 12, 16, 20, ...
Suku Pertama = 8 , Beda = 4
Maka rumus pola : Un = 4n + 4
Pola barisan bertingkat [ jeruk ]
1, 4, 9, ... [ a = 1 ]
+3, +5, ... [ b = 3 ]
+2, ... [ c = 2 ]
Maka rumus pola :
Un = a + b( n - 1 ) + c/2( n - 1 )( n - 2 )
Un = 1 + 3( n - 1 ) + 2/2( n² - 3n + 2 )
Un = 1 + 3n - 3 + n² - 3n + 2
Un = n² + 3n - 3n + 3 - 3
Un = n²
Hasil / Result
n² = Un
n² = 169
n = √169
n = 13 [ suku ke - 13 ]
---
Un = 4n + 4
U13 = 4(13) + 4
U13 = 52 + 4
U13 = 56 pohon apel { c. }
Semoga bisa membantu
[tex] \boxed{ \colorbox{navy}{ \sf{ \color{lightblue}{ Answer\:by\: BLUEBRAXGEOMETRY}}}} [/tex]