Question

Pliss tolong jawab yaa kk pake cara no 7

lumayan kak 15 poin

Answer 1

1.1/2 n (n+4)
[suku pertama] =1/2·1 (1+4) = 1/2 (5) = 5/2 = 2,5
[suku kedua] = 1/2·2 (2+4) = 1 (6) = 6
[suku ketiga] = 1/2·3 (3+4)= 3/2 (7) = 21/2 = 10,5
[suku keempat] = 1/2·4 (4+4) = 2 (8) = 16
[suku kelima] = 1/2·5 (5+4) = 5/2 (9) = 45/2 = 22,5
2.3^n-2 +2
[suku pertama] = 3^1-2 +2 = 3^-1 +2 = 0,3+2 = 2,3
[suku kedua] = 3^2-2 +2 = 1+2 = 3
[suku ketiga] = 3^3-2 + 2 = 3+2 = 5
[suku keempat] = 3 ^4-2 +2 = 3^2 +2 = 9+2= 11
[suku kelima] = 3^5-2 +2 = 3^3 +2 =27 +2 = 29
3. tidak dapat saya jawab karena saya kurang mengerti soalnya
4. (n-5) (n+2)
[suku pertama] = (1-5) (1+2) = (-4) (3)= (-12)
[suku kedua] = (2-5) (2+2) = (-3) (4) = (-12)
[suku ketiga] = (3-5) (3+2) = (-2) (5)= (-10)
[suku keempat]= (4-5) (4+2) = (-1) (6) = (-6)
[suku kelima] = (5-5) (5+2) = 0 (7)= 0
5.n(4n-1)/2
[suku pertama] = 1(4-1)/2 = 3/2 = 1,5
[suku kedua] = 2 (4·2-1)/2= 2 (8-1)/2 = 2(7)/2 = 7
[suku ketiga] = 3 (4·3-1)/2=3(12-1)/2= 3(11)/2=33/2=16,5
[suku keempat]= 4 (4·4-1)/2= 4(16-1)/2 = 4(15)/2 = 60/2= 30
[suku kelima] = 5 (4·5-1)/2 = 5 (20-1)/2 = 5 (19)/2= 95/2= 47,5