Materi : Lingkaran
Pb = 96/360 × πd
Pb = 4/15 × 22/7 × 21 cm
Pb = 4/15 × 22 × 3 cm
Pb = 4/15 × 66 cm
Pb = 264/15
Pb = 17,6 cm { d. }
L( r = 25 ) - L( r = 24 )
= π × r² - π × r²
= 625π - 576π
= 49π
= 7 × 22
= 154 cm² { a. }
∠BOC = ∠AOD = 135° - 90° = 45°
AC = ∠AOC/∠BOC × BC
AC = 135°/45° × 12 cm
AC = 27/9 × 12 cm
AC = 3 × 12 cm
AC = 36 cm { c. }
Semoga bisa membantu
[tex] \boxed{ \colorbox{darkblue}{ \sf{ \color{lightblue}{ answered\:by\: BLUEBRAXGEOMETRY}}}} [/tex]
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Materi : Lingkaran
Soal Nomor 3
Pb = 96/360 × πd
Pb = 4/15 × 22/7 × 21 cm
Pb = 4/15 × 22 × 3 cm
Pb = 4/15 × 66 cm
Pb = 264/15
Pb = 17,6 cm { d. }
Soal Nomor 4
L( r = 25 ) - L( r = 24 )
= π × r² - π × r²
= 625π - 576π
= 49π
= 7 × 22
= 154 cm² { a. }
Soal Nomor 5
∠BOC = ∠AOD = 135° - 90° = 45°
AC = ∠AOC/∠BOC × BC
AC = 135°/45° × 12 cm
AC = 27/9 × 12 cm
AC = 3 × 12 cm
AC = 36 cm { c. }
Semoga bisa membantu
[tex] \boxed{ \colorbox{darkblue}{ \sf{ \color{lightblue}{ answered\:by\: BLUEBRAXGEOMETRY}}}} [/tex]