mAl2O3=2*27 u+3*16 u=102 u
54 u---x%
102 u---100%
x=52,94%Al
100%-52,94%=%O
%O=47,06%
Stosunek masowy:
mAl:mO=54:48=9:8
Stosunek molowy:
nAl:nO=2:3
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mAl2O3=2*27 u+3*16 u=102 u
54 u---x%
102 u---100%
x=52,94%Al
100%-52,94%=%O
%O=47,06%
Stosunek masowy:
mAl:mO=54:48=9:8
Stosunek molowy:
nAl:nO=2:3