Materi : Bentuk Akar dan Pangkat
A. 5/√6 = 5√6/(√6)² = ⅚√6
B. 5/2√3 = 5(2√3)/(2√3)² = 10/12.√3 = ⅚√3
C. 2√2/√3 = 2√2(√3)/(√3)² = 2√6/3 = ⅔√6
D. 2√2/6√6 = √2/3√6 = 3√12/3(6) = 6√3/18 = ⅓√3
E. 4/( 5+√6 ) = 4( 5-√6 )/( 25 - 6 ) = 4/19( 5 - √6 )
F. 3√5/(√3+√5) = 3(5+√15)/(3-5) = -⅔( 5+√15 )
G. 5/(4-√6) = 5(4+√6)/(16-6) = ½( 4 + √6 )
H. 3/(5-√11) = 3(5+√11)/(25-11) = 3/14( 5 + √11 )
Semoga bisa membantu
[tex] \boxed{ \colorbox{darkblue}{ \sf{ \color{lightblue}{ answered\:by\: BLUEBRAXGEOMETRY}}}} [/tex]
Penjelasan dengan langkah-langkah:
Semoga cukup jelas dan terbantu y....
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Materi : Bentuk Akar dan Pangkat
A. 5/√6 = 5√6/(√6)² = ⅚√6
B. 5/2√3 = 5(2√3)/(2√3)² = 10/12.√3 = ⅚√3
C. 2√2/√3 = 2√2(√3)/(√3)² = 2√6/3 = ⅔√6
D. 2√2/6√6 = √2/3√6 = 3√12/3(6) = 6√3/18 = ⅓√3
E. 4/( 5+√6 ) = 4( 5-√6 )/( 25 - 6 ) = 4/19( 5 - √6 )
F. 3√5/(√3+√5) = 3(5+√15)/(3-5) = -⅔( 5+√15 )
G. 5/(4-√6) = 5(4+√6)/(16-6) = ½( 4 + √6 )
H. 3/(5-√11) = 3(5+√11)/(25-11) = 3/14( 5 + √11 )
Semoga bisa membantu
[tex] \boxed{ \colorbox{darkblue}{ \sf{ \color{lightblue}{ answered\:by\: BLUEBRAXGEOMETRY}}}} [/tex]
Penjelasan dengan langkah-langkah:
Semoga cukup jelas dan terbantu y....