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orde Br2 = 1
pers. laju: v = k[NO][Br2]
masukkan data diperc.2:
k = v / [NO][Br2]
k = 12 / (0,1)(0,1)
k = 1200
v = 1200[NO][Br2]
v = 1200(0,01)(0,03)
v = 0,36 Ms-1 (B)