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gradien garis x - 3y = 7, m1 = ⅓
garis tegak lurus :
m1 × m2 = -1
⅓ × m2 = -1
m2 = -3
PGS Lingkaran x² + y² + 2x + 8y + 1 = 0 => (x + 1)² + (y + 4)² = 16 yg bergradien m = -3.
(y - b) = m(x - a) ± r√(m² + 1)
(y + 4) = -3(x + 1) ± 4√((-3)² + 1)
y + 4 = -3x - 3 ± 4√10
y = -3x - 7 ± 4√10