Penjelasan dengan langkah-langkah:
P E L U A N G
1) n(Fh) = 34 + 42 + 24 = 100
a. PE(2G) = 34%
b. PE(A, G) = 42%
c. PE(2A) = 24%
2) n(Fh) = 32
n(Bp) = 120
a. PE(1) = 10/120 = 1/12
b. PE(2) = 14/120 = 7/60
c. PE(3) = 8/120 = 1/15
d. PE( < 3) = 24/120 = 1/5
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Penjelasan dengan langkah-langkah:
P E L U A N G
1) n(Fh) = 34 + 42 + 24 = 100
a. PE(2G) = 34%
b. PE(A, G) = 42%
c. PE(2A) = 24%
2) n(Fh) = 32
n(Bp) = 120
a. PE(1) = 10/120 = 1/12
b. PE(2) = 14/120 = 7/60
c. PE(3) = 8/120 = 1/15
d. PE( < 3) = 24/120 = 1/5