Odpowiedź:
[tex]\left \{ {{x-3y=5} \atop {2x-y=3}} \right. =\left \{ {{x=5+3y} \atop {2x-y=3}} \right. \\\\2(5+3y)-y=3\\10+6y-y=3\\6y-y=3-10\\5y=-7/5\\y=-\frac{7}{5} \\\\x=5+3y\\x=5+3*(-\frac{7}{5} )\\x=5-\frac{21}{5} \\x=\frac{4}{5}[/tex]
Szczegółowe wyjaśnienie:
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Odpowiedź:
[tex]\left \{ {{x-3y=5} \atop {2x-y=3}} \right. =\left \{ {{x=5+3y} \atop {2x-y=3}} \right. \\\\2(5+3y)-y=3\\10+6y-y=3\\6y-y=3-10\\5y=-7/5\\y=-\frac{7}{5} \\\\x=5+3y\\x=5+3*(-\frac{7}{5} )\\x=5-\frac{21}{5} \\x=\frac{4}{5}[/tex]
Szczegółowe wyjaśnienie: