mira20022003
Luas ACD = 25cm² a x t /2 = 25 5t = 25(2) = 50 t = 50 : 5 = 10cm AE²= BE² + AB² = 24² + 10² = 576 + 100 = 676 AE = akar dari 676 = 26cm SEMOGA BERMANFAAT YAAA
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kanawulan7
Luas ACD = Luas ABD - Luas ABC 25 = (1/2 x a x t) - (1/2 x a x t) 25 = (1/2 x BD x AB) -(1/2 x BC x AB) 25 = (1/2 x 13 x AB) - (1/2 x 8 x AB) 25 = 13/2 AB - 8/2 AB 25 = 5/2 AB 5 AB = 25 x 2 5 AB = 50 AB = 10
a x t /2 = 25
5t = 25(2) = 50
t = 50 : 5 = 10cm
AE²= BE² + AB²
= 24² + 10²
= 576 + 100
= 676
AE = akar dari 676 = 26cm
SEMOGA BERMANFAAT YAAA
25 = (1/2 x a x t) - (1/2 x a x t)
25 = (1/2 x BD x AB) -(1/2 x BC x AB)
25 = (1/2 x 13 x AB) - (1/2 x 8 x AB)
25 = 13/2 AB - 8/2 AB
25 = 5/2 AB
5 AB = 25 x 2
5 AB = 50
AB = 10
dengan rumus pytagoras
AE² = AB²+BE²
AE = √10²+24²
AE = √100 + 576
AE = √676
AE = 26
Jawab B