Jawaban:
No. 1
[tex] \frac{4a {b}^{2} + 2b {c}^{2} }{2abc} = \frac{4a {b}^{2} }{2abc} + \frac{2b {c}^{2} }{2abc} = \frac{2b}{c} + \frac{c}{a} [/tex]
No. 2
[tex] - 3 {x}^{2} (2x + 4) = - 6 {x}^{3} - 12 {x}^{2} [/tex]
No. 3
[tex]3 {a}^{2} b(5 - 2a {b}^{2} + 3ab - {b}^{2} ) = 15 {a}^{2} b - 6 {a}^{3} {b}^{3} + 3 {a}^{3} {b}^{2} - 3 {a}^{2} {b}^{3} [/tex]
No. 4
[tex] - 2ab(3 {a}^{2} b - 2ab + 7a {b}^{2} ) = - 6 {a}^{3} {b}^{2} + 4 {a}^{2} {b}^{2} - 14 {a}^{2} {b}^{3} [/tex]
No. 5
[tex] \frac{(36 {x}^{3} {y}^{2}z)( - 2 {x}^{4} {y}^{3} {z}^{4} )}{( {x}^{2} {y}^{2} z)(9 {x}^{5} {y}^{2} z) } = \frac{ - 72 {x}^{7} {y}^{5} {z}^{5} }{9 {x}^{7} {y}^{4} {z}^{2} } = - 8y {z}^{3} [/tex]
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Jawaban:
No. 1
[tex] \frac{4a {b}^{2} + 2b {c}^{2} }{2abc} = \frac{4a {b}^{2} }{2abc} + \frac{2b {c}^{2} }{2abc} = \frac{2b}{c} + \frac{c}{a} [/tex]
No. 2
[tex] - 3 {x}^{2} (2x + 4) = - 6 {x}^{3} - 12 {x}^{2} [/tex]
No. 3
[tex]3 {a}^{2} b(5 - 2a {b}^{2} + 3ab - {b}^{2} ) = 15 {a}^{2} b - 6 {a}^{3} {b}^{3} + 3 {a}^{3} {b}^{2} - 3 {a}^{2} {b}^{3} [/tex]
No. 4
[tex] - 2ab(3 {a}^{2} b - 2ab + 7a {b}^{2} ) = - 6 {a}^{3} {b}^{2} + 4 {a}^{2} {b}^{2} - 14 {a}^{2} {b}^{3} [/tex]
No. 5
[tex] \frac{(36 {x}^{3} {y}^{2}z)( - 2 {x}^{4} {y}^{3} {z}^{4} )}{( {x}^{2} {y}^{2} z)(9 {x}^{5} {y}^{2} z) } = \frac{ - 72 {x}^{7} {y}^{5} {z}^{5} }{9 {x}^{7} {y}^{4} {z}^{2} } = - 8y {z}^{3} [/tex]
Semoga membantu :D
Jangan Lupa Jadikan Jawaban Terbaik yaa :D
Wanwan selalu membantu mu :^
#MATEMATIKAMENYENANGKAN