Jawaban:
B.
Penjelasan dengan langkah-langkah:
|4x + 2| > |3x-3|
(4x+2)^2 - (3x-3)^2 > 0
(4x + 2 + 3x - 3) (4x + 2 - ( 3x -3 ))
(7x -1) (x + 5)
(7x-1)
7x - 1 = 0
7x = 1
x = 1/7
(x+5)
x + 5 = 0
x = -5
Uji titik, x = 0
(7(0) - 1) (-(0) + 5)
-1 x 5 = -5 >> negatif
> 0 >> positif
x < -5 atau x > 1/7
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Jawaban:
B.
Penjelasan dengan langkah-langkah:
|4x + 2| > |3x-3|
(4x+2)^2 - (3x-3)^2 > 0
(4x + 2 + 3x - 3) (4x + 2 - ( 3x -3 ))
(7x -1) (x + 5)
(7x-1)
7x - 1 = 0
7x = 1
x = 1/7
(x+5)
x + 5 = 0
x = -5
Uji titik, x = 0
(7(0) - 1) (-(0) + 5)
-1 x 5 = -5 >> negatif
> 0 >> positif
x < -5 atau x > 1/7