Question

Please yang jago fisik bantuin dong

Answer 1

4. p awal= p akhir
m₁v₁ + m₂v₂ = m₁v₁¹ + m₂v₂¹
0,440.3,70 + 0 = 0,440.v₁¹ + 0,220.v₂¹ (kedua ruas dibagi 0,220)
2.3,70 = 2v₁¹+v₂¹
7,4 = 2v₁¹ +v₂¹ ......................... (1)

Pada tumbukan lenting sempurna, e = 1

e = - (v₂¹-v₁¹)/v₂-v₁
-1 = v₂¹-v₁¹/-v₁
v₁ = v₂¹-v₁¹
3,70 = v₂¹-v₁¹
-v₁¹+v₂¹ = 3,70 ..................(2)

Persamaan 1 dan 2 eliminasi

2v₁¹ + v₂¹ =7,4
-v₁¹+v₂¹ = 3,7
-------------------   -
3v₁¹ = 3,7
v₁¹ = 3,7/3 = 1,23 m/s

-v₁¹ +v₂¹ = 3,7
-1,23 +v₂¹ = 3,7
v₂¹ = 3,7 + 1,23 = 3,93 m/s