[tex]10)cos \: 60 = \frac{sisi \: samping}{sisi \: miring} \\ \frac{1}{2} = \frac{x}{24} \\ x = \frac{24}{2} \\ x = 12 \: cm \: [ D ] [/tex]
[tex]11)jarak \: kapal = jarak \: ke \: timur +jarak \: ke \: utara \\ phytagoras \\ {x}^{2} = {15}^{2} + {8}^{2} \\ {x}^{2} = 225 + 64 \\ {x}^{2} = 289 \\ x = \sqrt{289} \\ x = 17 \: km [ B ] [/tex]
12) Segitiga Lancip[B]
[tex]13)(lebar)^{2} \: =( diagonal) ^{2} - (panjang)^{2} \\ {x}^{2} = {30}^{2} - {24}^{2} \\ {x}^{2} = 900 - 576 \\ {x}^{2} = 324 \\ x = \sqrt{324} = 18 \\ luas \: = p \times l = 24 \times 18 = 432 \: {cm}^{2} [ C ] [/tex]
Verified answer
Jawaban:
[tex]10)cos \: 60 = \frac{sisi \: samping}{sisi \: miring} \\ \frac{1}{2} = \frac{x}{24} \\ x = \frac{24}{2} \\ x = 12 \: cm \: [ D ] [/tex]
[tex]11)jarak \: kapal = jarak \: ke \: timur +jarak \: ke \: utara \\ phytagoras \\ {x}^{2} = {15}^{2} + {8}^{2} \\ {x}^{2} = 225 + 64 \\ {x}^{2} = 289 \\ x = \sqrt{289} \\ x = 17 \: km [ B ] [/tex]
12) Segitiga Lancip [ B ]
[tex]13)(lebar)^{2} \: =( diagonal) ^{2} - (panjang)^{2} \\ {x}^{2} = {30}^{2} - {24}^{2} \\ {x}^{2} = 900 - 576 \\ {x}^{2} = 324 \\ x = \sqrt{324} = 18 \\ luas \: = p \times l = 24 \times 18 = 432 \: {cm}^{2} [ C ] [/tex]