5. B. 576cm³
6. D. 9.240cm³
7. (Tidak ada pada Option) 3.850 cm²
5. Volume Bangun Limas segi empat : ⅓×L. Alas×Tinggi
= ⅓ × (s×s) × t
= ⅓ × (12×12) × 12
= ⅓ × 144 × 12
= 144 × 4 = 576cm³
6. Volume Bangun Kerucut : ⅓ × L Alas × Tinggi
= ⅓ × (phi × r²) × t
= ⅓ × (22/7 × 21²) × 20
= ⅓ × (22/7 × 21 × 21) × 20
= ⅓ × (22 × 3 × 21) × 20
= ⅓ × 1386 × 20
= 462 × 20 = 9.240cm³
7. Luas Permukaan Bola : 4 × L Alas
= 4 × (Phi × r²)
= 4 × (3,14 × (35÷2)²)
= 4 × (3,14 × 17,5²)
= 4 × (3,14 × 306,25)
= 4 × 961,625
= 3846,5cm²
Maaf kalau ada yang salah ya
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Jawaban :
5. B. 576cm³
6. D. 9.240cm³
7. (Tidak ada pada Option) 3.850 cm²
Cara :
5. Volume Bangun Limas segi empat : ⅓×L. Alas×Tinggi
= ⅓ × (s×s) × t
= ⅓ × (12×12) × 12
= ⅓ × 144 × 12
= 144 × 4 = 576cm³
6. Volume Bangun Kerucut : ⅓ × L Alas × Tinggi
= ⅓ × (phi × r²) × t
= ⅓ × (22/7 × 21²) × 20
= ⅓ × (22/7 × 21 × 21) × 20
= ⅓ × (22 × 3 × 21) × 20
= ⅓ × 1386 × 20
= 462 × 20 = 9.240cm³
7. Luas Permukaan Bola : 4 × L Alas
= 4 × (Phi × r²)
= 4 × (3,14 × (35÷2)²)
= 4 × (3,14 × 17,5²)
= 4 × (3,14 × 306,25)
= 4 × 961,625
= 3846,5cm²
Maaf kalau ada yang salah ya