Question

Please, jawabkan yang nomor 1 dan 2, saya butuh sekali jawabannya

Answer 1

1)
a)
2^5 . 2^9 . 2^12
= 2^(5 + 9 + 12) = 2^26

b)
2^5 . 3^6 . 4^5
= 2^5 . 3^6 . (2^2)^5
= 2^5 . 2^10 . 3^6
= 2^15 . 3^6

c)
(2^5 . 3^5 . 4^2) / 12^2
= (2^5 . 3^5 . 2^4) / (2^4 . 3^2)
= (2^9 . 3^5) / (2^4 . 3^2)
= 2^5 . 3^3

d)
((-5)^6 . 25^2) / 125
= 5^6 . 5^4 / 5^3
= 5^7

e)
(3^7 . 7^3 . 2) / 42^3
= (3^7 . 7^3 . 2) / (2^3 . 3^3 . 7^3)
= 2^-2 . 3^4
= 3^4 / 2^2

2)
a)
2x^3 . 7x^4 . (3x)^2
= 2x^2 . 7x^4 . 9x^2
= 2 . 7 . 9 . x^2 . x^4 . x^2
= 126x^8

b)
(-2p / q) . (-q)^4 . 2/5 p^2
= -2 . 2/5 . p . q^-1 . q^4 . p^2
= -4/5 p^3 q^3

c)
y^5 . (xy)^3 . (1 / x^2y)
= y^5 . x^3 . y^3 . x^-2 . y^-1
= x y^7

d)
(abc)^4 . (3 / (bc)^3) . (b^3 / 27 a^5)
= 3 . 1/27 . a^4 . b^4 . c^4 . b^-3 . c^-3 . b^3 . a^-5
= 1/9 a^-1 b^4 c
= (b^4 c) / (9a)

e)
(-4a^3 . 2b^3) / [(8a / b)]
= (-8 . a^3 . b^3) . (b / 8a)
= -8 . 1/8 . a^3 . b^3 . b . a^-1
= -1 . a^2 . b^4
= -(a^2 b^4)

f)
(1 / x^2 y) . (2x / 3y^2) . (5 / 3x) . (4y)^2
= (x^-2 . y^-1) . (2/3 . x . y^-2) . (5/3 . x^-1) . 16 y^2
= 2/3 . 5/3 . 16 . x^-2 . y^-1 . x . y^-2 . x^-1 . y^2
= 160/9 . x^-2 . y^-1
= 160 / 9 x^2 y

g)
(-ab)^3 . (-b / 2a)^4 . (3a . b)^5
= -(a^3 . b^3) . (b^4 / 16 a^4) . (243 a^5 . b^5)
= -1 . 1/16 . 243 . a^3 . b^3 . b^4 . a^-4 . a^5 . b^5
= -243 / 16 . a^4 . b^12
= (-243 a^4 b^12) / 16

h)
(24 a^3 b^8) / (6 a^5 b) . [(4 a b^3) / (2 a^3)]^2
= (24/6 . a^3 . b^8 . a^-5 . b^-1) . [4/2 . a . b^3 . a^-3]^2
= (4 . a^-2 . b^7) . [2 . a^-2 . b^3]^2
= 4 . a^-2 . b^7 . 4 . a^-4 . b^6
= 16 . a^-6 . b^13
= (16 b^13) / a^6