Penjelasan dengan langkah-langkah:
3. perbandingan a:t = 4:3
luas segitiga : 1/2 a.t
216 = 1/2.4x.3x
432= 12x^2
432/12 = x^2
36 = x^2
6 = x
tinggi 3x = 6(3) = 18 cm
4.keliling segitiga = AC+AB+BC
(x+3) + 2x +(2x+3) =36
5X+6 = 36
5X = 30
x=6
nilai x =6
Luas segitiga = 1/2 a.t
a=AB=2x=2(6)=12
t=AC=(x+3)=6+3=9
L =1/2.12.9
L=6.9
L=54
5. 1/2.000.000 = 4/x
x=2.000.000 x 4
x=8.000.000
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Penjelasan dengan langkah-langkah:
3. perbandingan a:t = 4:3
luas segitiga : 1/2 a.t
216 = 1/2.4x.3x
432= 12x^2
432/12 = x^2
36 = x^2
6 = x
tinggi 3x = 6(3) = 18 cm
4.keliling segitiga = AC+AB+BC
(x+3) + 2x +(2x+3) =36
5X+6 = 36
5X = 30
x=6
nilai x =6
Luas segitiga = 1/2 a.t
a=AB=2x=2(6)=12
t=AC=(x+3)=6+3=9
L =1/2.12.9
L=6.9
L=54
5. 1/2.000.000 = 4/x
x=2.000.000 x 4
x=8.000.000