No. 1
Keliling
= 2 π r
= 2 × 22/7 × 21
= 132 cm
↓
Panjang lintasan
= 132 × 2500
= 330 000 cm
= 3,3 km
No. 2
= π d
= 22/7 × 105
= 330 m
Banyak tumbuhan palm
= 330 : 6
= 55
No. 3
Luas
= π r²
= 22/7 × 28 × 28
= 2464 m²
Biaya
= 2464 × 7 500
= 18 480 000
No. 4
= 1/2 π r²
= 1/2 × 22/7 × 7 × 7
= 77 m²
= 1/2 × 2πr
= 1/2 × 2 × 22/7 × 7
= 22/7 × 7
= 22 m
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No. 1
Keliling
= 2 π r
= 2 × 22/7 × 21
= 132 cm
↓
Panjang lintasan
= 132 × 2500
= 330 000 cm
= 3,3 km
No. 2
Keliling
= π d
= 22/7 × 105
= 330 m
↓
Banyak tumbuhan palm
= 330 : 6
= 55
No. 3
Luas
= π r²
= 22/7 × 28 × 28
= 2464 m²
↓
Biaya
= 2464 × 7 500
= 18 480 000
No. 4
Luas
= 1/2 π r²
= 1/2 × 22/7 × 7 × 7
= 77 m²
Keliling
= 1/2 × 2πr
= 1/2 × 2 × 22/7 × 7
= 22/7 × 7
= 22 m