Question

please bantuin .....​

Answer 1

Integral dari 9x⁻² adalah 9/(-2 + 1) * x^(-2 + 1) + C = -9x⁻¹ + C.

Integral dari 9x^(1/2) adalah 9/(1/2 + 1) * x^(1/2 + 1) + C = 6x√x + C.

Answer 2

integral

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[tex] \displaystyle\sf\int9x^ {- 2} \: dx &= \displaystyle \sf \frac{9}{ - 2 + 1} \: {x}^{ - 2 + 1} \: + \: c \\ \\&= \displaystyle\sf - \frac{9}{x} \: + \: c[/tex]

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[tex] \displaystyle \sf \int \: 9 {x}^{ \frac{1}{2} } \: dx & = \frac{9}{ \frac{1}{2} + 1 } \: {x}^{ \frac{1}{2} \: + \: 1 } \: + \: c \\ \\ & = \displaystyle \sf 9 \times \frac{2}{3} \: {x}^{ \frac{3}{2} } \: + \: c \\ \\ & \: = \displaystyle \sf 6x \sqrt{x} \: + \: c[/tex]