Question

pils tolong di jawab kk besok di kumpul kan plis dijawab ​

Answer 1

Jawaban:

pH 9

Penjelasan:

Mol CH3COOH

= M x V

= 0,2 x 100

= 20 mmol

Mol NaOH

= 0,2 x 100

= 20 mmol

Persamaan Reaksi:

CH3COOH + NaOH --> CH3COONa + H2O

20 mmol 20 -

20 20 20 .

- - 20 mmol

Asam Lemah dan Basa Kuat Habis Bereaksi,

Molaritas Garam

= Mol/V total

= 20 mmol/200 ml

= 0,1 M

Konsentrasi ion OH-

= akar ( Kw/Ka x M garam)

= akar ( 10^(-14)/10^(-5) x 0,1

= akar 0,1 x 10^(-9)

= akar 10^(-10)

= 10^(-5)

pOH

= -log 10^(-5)

= 5

pH

= 14 - pOH

= 14 -5

= 9

Answer 2

Jawaban:

n CH3COOH = 0,2 M x 100 mL = 20 mmol

n NaOH = 0,2 M x 100 mL = 20 mmol

[H+] = a/g x ka

= 20/20 x 10*-5

= 10*-5

PH = 5