April 2019 0 12 Report
Pilne !!!
Równanie okręgu o środku S =(0,2) i promieniu r=\sqrt{3} ma postać ?
A. (x-2)^2+y^2=3
B. x^2+(y-2)^2=3
C. (x-2)^2+y^2=(pierwiastek z 3 )
D. x^2 + (y-2)^2=9

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