[tex]\frac{-4x-3}{x+1} \leq4x\\\\\frac{-4x-3}{x+1}-4x\leq 0\\\\\frac{-4x-3}{x+1}- \frac{4x\cdot(x+1)}{x+1} \leq 0\\\\\frac{-4x-3}{x+1}- \frac{4x^2+4x}{x+1} \leq 0\\\\\\\frac{-4x-4-(4x^2+4x)}{x+1} \leq 0\\\\\frac{-4x-4-4x^2-4x}{x+1} \leq 0\\\\\frac{-4x^2-8x-4}{x+1}\leq 0[/tex]
[tex](-4x^2-8x-4)\cdot(x+1)^2\leq 0\\\\-4(x+1)^2\cdot(x+1)^2\leq 0\\\\-4(x+1)^4\leq 0\\\\x=-1[/tex]
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[tex]\frac{-4x-3}{x+1} \leq4x\\\\\frac{-4x-3}{x+1}-4x\leq 0\\\\\frac{-4x-3}{x+1}- \frac{4x\cdot(x+1)}{x+1} \leq 0\\\\\frac{-4x-3}{x+1}- \frac{4x^2+4x}{x+1} \leq 0\\\\\\\frac{-4x-4-(4x^2+4x)}{x+1} \leq 0\\\\\frac{-4x-4-4x^2-4x}{x+1} \leq 0\\\\\frac{-4x^2-8x-4}{x+1}\leq 0[/tex]
[tex](-4x^2-8x-4)\cdot(x+1)^2\leq 0\\\\-4(x+1)^2\cdot(x+1)^2\leq 0\\\\-4(x+1)^4\leq 0\\\\x=-1[/tex]