θ = θ₀ + ω.t
12,5 = θ₀ + 3π/2 . 2,4
θ₀ = 12,5 - 11,3
θ₀ = 1,19 rad
θ₀ = 1,2 rad ( dibulatkan )
Jawaban. a
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θ = θ₀ + ω.t
12,5 = θ₀ + 3π/2 . 2,4
θ₀ = 12,5 - 11,3
θ₀ = 1,19 rad
θ₀ = 1,2 rad ( dibulatkan )
Jawaban. a
ω= 3π/2
t= 2,4 s
θ= 12,5
θ-θο= ω.t
12,5-(3π/2.2,4)
≈1,19 = 1,2 rad.