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0,25% = 0,0025
mol/dm3
2)
mol/dm3
3)
2 HCl + BaO ---> BaCl₂ + H₂O
25 cm3 = 0,025 dm3
mola
2 mole kwasu --- 1 mol tlenku
x --- 0,00125
x = 0,0025 mola kwasu
dm3 cm3