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= 0,2 x 100
= 20 mmol
mol HCl = M x V
= 0,2 x 100
= 20 mmol
Persamaan reaksi :
NH₃ + HCl → NH₄Cl
a 20 20
r 20 20
____________________
s - - 20 mmol
Karena basa lemah (NH₃) dan asma kuat (HCl) habis bereaksi, maka terbentk sistem hidrolisis garam
mol NH₄Cl = 20 mmol
mol NH₄⁺ = 20 mmol
M NH₄⁺ = mol/Volume total
= 20/(100 + 100)
= 20/200
= 0,1 M
[H⁺] = √Kw/Kb • M kation garam
= √10⁻¹⁴/10⁻⁵ • 0,1
= √10⁻¹⁰
= 10 ⁻⁵
pH = -log [H⁺]
= -log [10⁻⁵]
= 5
Jadi, pH larutan yang terebntuk adalah 5