diket:
M: 0,002 = 2*10^-3
b: 2 -> Ba(OH)2
dijawab:
[OH-] : b*M
[OH-] : 2*2*10^-3
[OH-] : 4*10^-3
•pOH : - log 4*10^-3
pOH : - log 4 - log 10^-3
pOH : 3 - log 4
•pH : 14 - (3 - log4)
pH : 11 + log 4
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diket:
M: 0,002 = 2*10^-3
b: 2 -> Ba(OH)2
dijawab:
[OH-] : b*M
[OH-] : 2*2*10^-3
[OH-] : 4*10^-3
•pOH : - log 4*10^-3
pOH : - log 4 - log 10^-3
pOH : 3 - log 4
•pH : 14 - (3 - log4)
pH : 11 + log 4