Question

Ph larutan 500 ml Ca(OH)2 0,0005M adalah

Answer 1

N Ca(OH)2 = 0,0005 × 500 = 0,25 mmol

Ca(OH)2 → Ca^2+ + 2OH^-
M 0,25 - -
R 0,25 0,25 0,5
S - 0,25 0,5

[OH^-] = 0,5/500 = 0,001 M

pOH = - log [OH^-]
pOH = - log 0,001
pOH = 3

pH = 14 - pOH
pH = 14 - 3
pH = 11