Question

Ph asam H x bisa diketahui konsentrasinya 0,1 M dan ka 10^-7 adalah

Answer 1

Verified answer

Gunakan rumus asam lemah

[H+] = (10^-7 × 0.1)^1/2 = 10^-4

pH = -log 10^-4
= 4

Answer 2

[H+] = √ka x Ma = √10^-7 x 10^-1 = √10^-8 = 10^-4
pH = - Log [H+] = - Log 10^-4 = 4 - Log 1 = 4-0 = 4
jasi pH nya adalah 4