PH 500 ml (NH4)2SO4 0,1 M (Kb=2x10 pangkat -5 adalah...
Tolong bantuannya :)
Tolong bantuannya :)
fatihahalhusna
![$ \begin {align}[H^+]&=\sqrt{\frac{K_w\times{NH^+_4}}{K_b}}\\&=\sqrt{\frac{10^{-14}\times0,2}{2\times10^{-5}}}\\&=10^{-5}\ M\\\\pH&=\boxed{\boxed{\bold{5}}} \end](https://tex.z-dn.net/?f=%24+%5Cbegin+%7Balign%7D%5BH%5E%2B%5D%26%3D%5Csqrt%7B%5Cfrac%7BK_w%5Ctimes%7BNH%5E%2B_4%7D%7D%7BK_b%7D%7D%5C%5C%26%3D%5Csqrt%7B%5Cfrac%7B10%5E%7B-14%7D%5Ctimes0%2C2%7D%7B2%5Ctimes10%5E%7B-5%7D%7D%7D%5C%5C%26%3D10%5E%7B-5%7D%5C+M%5C%5C%5C%5CpH%26%3D%5Cboxed%7B%5Cboxed%7B%5Cbold%7B5%7D%7D%7D%0A%5Cend "$ \begin {align}[H^+]&=\sqrt{\frac{K_w\times{NH^+_4}}{K_b}}\\&=\sqrt{\frac{10^{-14}\times0,2}{2\times10^{-5}}}\\&=10^{-5}\ M\\\\pH&=\boxed{\boxed{\bold{5}}} \end")
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davidzulandra
itu 0,2 dpt dr mana ya??
fatihahalhusna
(NH4)2SO4 = 0,1 jadi NH4+ = 2 x 0,1 =0,2
davidzulandra
makasih !!!
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