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ilość gram azotu:
50kg---------100%
x--------------21%
x=50kg*21%/100%
x=10,5kg=10500g azotu
ilość gram tlenku fosforu(V)
50kg---------100%
y-------------8%
y=50kg*8%/100%
y=4kg=4000g tlenku fosforu (V)
lub II sposobem
21%azotu--------------10500g
8% tlenku fosforu(V)----y
y=8%*10500g/21%
y=4000g
ilość gram tlenku potasu:
50kg--------100%
z--------------11%
z=50kg*11%/100%
z=5,5kg=5500g
lub II sposobem
21%azotu--------------10500g
11% tlenku potasu-----z
z=11%*10500g/21%
z=5500g
lub
8% tlenku fosforu(V)------4000g
11% tlenku potasu--------z
z=11%*4000g/8%
z=5500g
Proszę:-)
mr=50kg
mN=21*50000/100%=10500g
mP₄O₁₀=8*50000/100%=4000g
mK₂O=11*50000/100%=5500g