Materi : Integral
( Ba = 0 , Bb = -1 ) ∫ ( 2x³ - 3x² + 4x ) dx
∫ ( 2x³ - 3x² + 4x ) dx
= (2/4)x⁴ - (3/3)x³ + (4/2)x²
= ½x⁴ - x³ + 2x²
Batas atas ( Ba ) [ x = 0 ]
= ½(0)⁴ - 0³ + 2(0)²
= 0 - 0 + 0
= 0
Batas bawah ( Bb ) [ x = -1 ]
= ½(-1)⁴ - (-1)³ + 2(-1)²
= ½(1) - ( -1 ) + 2(1)
= ½ + 1 + 2
= 3½ atau 7/2
Hasil Integral ( Ba = 0 , Bb = -1 ) ∫ ( 2x³ - 3x² + 4x ) dx adalah Ba - Bb = 0 - 7/2 = -7/2
Semoga bisa membantu
[tex] \boxed{ \colorbox{darkblue}{ \sf{ \color{lightblue}{ answered\:by\: BLUEBRAXGEOMETRY}}}} [/tex]
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Verified answer
Materi : Integral
( Ba = 0 , Bb = -1 ) ∫ ( 2x³ - 3x² + 4x ) dx
Hasil Integral
∫ ( 2x³ - 3x² + 4x ) dx
= (2/4)x⁴ - (3/3)x³ + (4/2)x²
= ½x⁴ - x³ + 2x²
Nilainya
Batas atas ( Ba ) [ x = 0 ]
= ½(0)⁴ - 0³ + 2(0)²
= 0 - 0 + 0
= 0
Batas bawah ( Bb ) [ x = -1 ]
= ½(-1)⁴ - (-1)³ + 2(-1)²
= ½(1) - ( -1 ) + 2(1)
= ½ + 1 + 2
= 3½ atau 7/2
Kesimpulan
Hasil Integral ( Ba = 0 , Bb = -1 ) ∫ ( 2x³ - 3x² + 4x ) dx adalah Ba - Bb = 0 - 7/2 = -7/2
Semoga bisa membantu
[tex] \boxed{ \colorbox{darkblue}{ \sf{ \color{lightblue}{ answered\:by\: BLUEBRAXGEOMETRY}}}} [/tex]