Question

Pertanyaan tentang Integral Tentu:
a. Hitunglah ∫₀⁻₁ (2x³ - 3x² + 4x) dx.
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Answer 1

Verified answer

Materi : Integral

( Ba = 0 , Bb = -1 ) ∫ ( 2x³ - 3x² + 4x ) dx

Hasil Integral

∫ ( 2x³ - 3x² + 4x ) dx

= (2/4)x⁴ - (3/3)x³ + (4/2)x²

= ½x⁴ - x³ + 2x²

Nilainya

Batas atas ( Ba ) [ x = 0 ]

= ½(0)⁴ - 0³ + 2(0)²

= 0 - 0 + 0

= 0

Batas bawah ( Bb ) [ x = -1 ]

= ½(-1)⁴ - (-1)³ + 2(-1)²

= ½(1) - ( -1 ) + 2(1)

= ½ + 1 + 2

= 3½ atau 7/2

Kesimpulan

Hasil Integral ( Ba = 0 , Bb = -1 ) ∫ ( 2x³ - 3x² + 4x ) dx adalah Ba - Bb = 0 - 7/2 = -7/2

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