Question

Persegi ABCD memiliki panjang BC=6y+20 keliling ABCD=200cm maka luas persegi ABCD...

Answer 1

Keliling persegi = 4xpanjang
200 = 4(6y+20)
200 = 24y+80
120 = 24y
5 = y
Luas = panjang x panjang
(6y+20)(6y+20)
(30+20)(30+20)
(50)(50)
2500cm.

Answer 2

Keliling = 4s
200 = 4 (6y + 20)
200 = 24y + 80
200 - 80 = 24y
120 = 24 y
120/24 = y
5 = y

Luas = (6y + 20) (6y + 20)
= (5.6 + 20) (5.6 + 20)
= (30 + 20) (30 + 20)
= 50 × 50
= 2500 cm2