Question

Persamaan x²+7x-18=0 mempunyai akar2 p&q.Tentukan persamaan kuadrat baru yg akar2 nya p+3 dan q+3

Answer 1

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x² +7x - 18 = 0
a= 1, b = 7, c = -18
p+q = -b/a = - 7
pq = c/a = - 18
persamaan kuadrat baru  x² - (p+3+q+3) x + (p+3)(q+3) = 0
x² -(p+q+6) x + (pq + 3(p+q) + 9) =0
x² -(-7+6) x + (-18 + 3(-7) + 9) = 0
x² + x - 30 = 0