berarti kan =
[2+px, 1 + 2x] [1,x] = 0
[2+px + x + 2x²] = 0
2x² + (p+1)x+ 2 = 0
x1 .x2 = 1
4x2.x2 = 1
4x2² = 1
x2² = 1/4
x2 = 1/2
x1 = 4(1/2) = 2
jadi :
x1 + x2 = (-p-1)/2
2 + 1/2 = (-p-1)/2
5/2 = (-p-1)/2
-p-1 = 5
-p = 4
p = -4
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
berarti kan =
[2+px, 1 + 2x] [1,x] = 0
[2+px + x + 2x²] = 0
2x² + (p+1)x+ 2 = 0
x1 .x2 = 1
4x2.x2 = 1
4x2² = 1
x2² = 1/4
x2 = 1/2
x1 = 4(1/2) = 2
jadi :
x1 + x2 = (-p-1)/2
2 + 1/2 = (-p-1)/2
5/2 = (-p-1)/2
-p-1 = 5
-p = 4
p = -4