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pusat (a,b) = (3,2)
menyinggung x = 1 maka
r = a-1= 3-1 = 2
Persamaan lingkaran
(x-a)²+(y-b)² = r²
(x-3)²+(y-2)² = 2²
x²-6x+9+y²-4y+4 = 4
x²+y²-6x-4y +9=0