Jawab:y = 2x + 5, nilai x = ½(y-5)
Penjelasan:Misal hasilnya y (f(x))f(x) = 2x + 5y = 2x + 52x + 5 = y2x = y - 5x = ½(y-5)f⁻¹(x) = ½(x-5)------------------------------f(x) = 2x + 5titik potong sumbu x, y = 00 = 2x + 52x = -5x = -⁵/₂Titik potong sumbu x = {-⁵/₂, 0}
titik potong sumbu y, x = 0y = 2(0) + 5y = 5Titik potong sumbu y = {0, 5}
------------------------------f⁻¹(x) = ½(x-5)titik potong sumbu x, y = 00 = ½(x-5)x-5 = 0x = 5Titik potong sumbu x = {5, 0}
titik potong sumbu y, x = 0y = ½(0-5)y = -⁵/₂Titik potong sumbu y = {0, -⁵/₂}
(Xcvi)
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Jawab:
y = 2x + 5, nilai x = ½(y-5)
Penjelasan:
Misal hasilnya y (f(x))
f(x) = 2x + 5
y = 2x + 5
2x + 5 = y
2x = y - 5
x = ½(y-5)
f⁻¹(x) = ½(x-5)
------------------------------
f(x) = 2x + 5
titik potong sumbu x, y = 0
0 = 2x + 5
2x = -5
x = -⁵/₂
Titik potong sumbu x = {-⁵/₂, 0}
titik potong sumbu y, x = 0
y = 2(0) + 5
y = 5
Titik potong sumbu y = {0, 5}
------------------------------
f⁻¹(x) = ½(x-5)
titik potong sumbu x, y = 0
0 = ½(x-5)
x-5 = 0
x = 5
Titik potong sumbu x = {5, 0}
titik potong sumbu y, x = 0
y = ½(0-5)
y = -⁵/₂
Titik potong sumbu y = {0, -⁵/₂}
(Xcvi)