rumus kuadratik / abc :
x = (-b ± √(b² - 4ac)) / 2a
jawab :
6x² + 4 = 12
6x² + 4 - 12 = 0
6x² - 8 = 0
a = 6
b = 0
c = -8
x = (-0 ± √(0² - 4(6)(-8)) / 2(6)
x = ± √192 / 12
x = ± 8√3 / 12
x = ± 2√3 / 3
maka, solusinya adalah ± 2√3 / 3
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rumus kuadratik / abc :
x = (-b ± √(b² - 4ac)) / 2a
jawab :
6x² + 4 = 12
6x² + 4 - 12 = 0
6x² - 8 = 0
a = 6
b = 0
c = -8
x = (-0 ± √(0² - 4(6)(-8)) / 2(6)
x = ± √192 / 12
x = ± 8√3 / 12
x = ± 2√3 / 3
maka, solusinya adalah ± 2√3 / 3