Question

Persamaan grafik fungsi kuadrat yang titik puncaknya di (4,0) serta melalui (0,-8) adalah?

Answer 1

(4,0) melalui ( 0,-8)
xp yp             x  y

y=a(x-xp)^2 +yp
-8=a(0-4)^2 +0
-8 = 16a
a = - 1/2

y= -1/2 ( x-4)^2 + 0
y= -1/2 ( x^2 - 8x +16)
y= -1/2x^2 +4x - 8

maaf kalo salah

Answer 2

(x,y) = (0,-8) (×p,yp) = (4,0) y=a(×-×p) "+yp =a(x-4)"+0 -8= a(0-4)"+0 -8=a.(-4)"+0 -8=16a a = -2 Sub, y=-2(×-4)"+0 y=-2(×"-8×+16)+0 y=-2×"+16×-32