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grafik fungsi kuadrat yang melalui titik(2,-6)dan memotong sumbu X di titik(1,0)dan(4,0)
jawab :
● memotong sumbu X pada (1,0) dan (4,0), maka gunakan :
y = a(x-x1)(x-x2)
y = a(x-1)(x-4)
y = a(x^2 - 5x + 4)
● melalui titik (2,-6)
y = a(x^2 - 5x + 4)
-6 = a((-2)^2 - 5(-2) + 4)
-6 = a (18)
a = - 1/3
maka :
y = a(x^2 - 5x + 4)
y = - 1/3(x^2 - 5x + 4)
y = -1/3 x^2 + 5/3 x - 4/3
silahkan dicheck kembali, semoga membantu