D. -⅓(x - 3)² - 1
Penjelasan dengan langkah-langkah:
P = (3, -1)
A = (0, -4)
[tex]ya = a(xa - xp {)}^{2} + yp \\ - 4 = a(0 - 3 {)}^{2} + ( - 1) \\ - 4 = 9a - 1 \\ 9a = -3 \\ a = - \frac{3}{9} = -\frac{1}{3} \\ [/tex]
[tex]y = - \frac{1}{3} (x - 3 {)}^{2} - 1 \\ y = -\frac{1}{3} ( {x}^{2} - 6x + 9) - 1 \\ -\frac{1}{3 } {x}^{2} + 2x - 4 = 0 \\ {x}^{2} + 6x - 12 = 0[/tex]
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Verified answer
D. -⅓(x - 3)² - 1
Penjelasan dengan langkah-langkah:
P = (3, -1)
A = (0, -4)
[tex]ya = a(xa - xp {)}^{2} + yp \\ - 4 = a(0 - 3 {)}^{2} + ( - 1) \\ - 4 = 9a - 1 \\ 9a = -3 \\ a = - \frac{3}{9} = -\frac{1}{3} \\ [/tex]
[tex]y = - \frac{1}{3} (x - 3 {)}^{2} - 1 \\ y = -\frac{1}{3} ( {x}^{2} - 6x + 9) - 1 \\ -\frac{1}{3 } {x}^{2} + 2x - 4 = 0 \\ {x}^{2} + 6x - 12 = 0[/tex]