Question

Persamaan garis yg tegak lurus dgn garis 2x+6y-12=0 dan melalui titik (-4,-2) tolong ya makasih

Answer 1

Gradien garis = -1/3
m2=3/1=3

y-y1=m(x-x1)
y-(-2)=3(x-(-4))
y+2=3(x+4)
y+2=3x+12
y=3x+12-2
y=3x+10

Answer 2

M1 = - 1/3
m2 = 3
titik = (-4,-2)

y-y1 = m(x-x1)
y+2 = 3(x+4)
y + 2 = 3x + 12
3x - y + 10 = 0