Question

persamaan garis yg melalui titik (1,43 dan (0,-2) adalah​

Answer 1

Verified answer

PeRsamaaN  Garis LUrus

[tex]\sf \dfrac{y-y_1}{y_2- y_1} = \dfrac{x_2- x_1}{x_2 - x_1}[/tex]

PGL melalui (1, 4)  dan (0, -2)

[tex]\sf \dfrac{y-y_1}{y_2- y_1} = \dfrac{x- x_1}{x_2 - x_1}[/tex]

[tex]\sf \dfrac{y-4}{-2-4} = \dfrac{x-1}{0- 1}[/tex]

[tex]\sf \dfrac{y-4}{-6} = \dfrac{x-1}{- 1}[/tex]

y -  4 =  6 (x - 1)
y -  4 =  6x -  6
y =  6x -  6 + 4

y =  6x - 2

Answer 2

Y - Y¹ / Y² - Y¹ = X - X1 / X² - X¹

Y - 4 / -2 - 4 = X - 1 / 0 - 1

Y - 4 / -(2 + 4) = X - 1 / -1

Y - 4 / - 6 = X - 1 / -1

Y - 4 = 6(X - 1)

Y - 4 = 6(X) - 6(1)

Y - 4 = 6X - 6

Y = 6X + (-6 + 4)

Y = 6X + (-(6 - 4)

Y = 6X + (-2)

Y = 6X - 2