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2x-3y = -9
2x-3y+9=0
garis 1 : 3x+2y-5= 0 ,m1= -3/9
garis 2 : (0,3), m2...?
garis 1 berpotongan garis 2 = m1 x m2= -1
= -3/9 x m2=-1
m2= -1 x -3/9
= 1 x 9/3
m2= 9/3
ditanya: persamaan garis...?
jawaban akhir :
y1= 3, x1= 0 , m= 9/3
rumus : y-y1 = m(x-x1)
: y-3 = 9/3(x-0)
: y-3 = 9/3x-0
y= 9/3x - 0 + 3
y= 9/3x + 3