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krna sejajar maka gradiennya sama
melalui titik (-2,5) maka pers garisnya adlh
y-y1 = m(x-x1)
y-5 = -2/3(x+2) --> kedua ruas dikali 3
3y-15 = -2(x+2)
3y-15 = -2x-4
2x+3y-15+4 = 0
2x+3y-11 = 0
jawaban : c
semoga membantu ya :)
y - y1 = m2(x - x1)
y - 5 = -2/3 (x + 2)
y - 5 = -2/3 x -4/3
y = -2/3 x + 11/3 atau
y + 2/3x - 11/3 = 0 supaya hilang per 3 nya mka kta kalikn 3 mnjadi
3y + 2x - 11 = 0 jawabannya C