Question

Persamaan garis yang melalui titik (6,2) dan (-3,-4) adalah

Answer 1

Y-y1 = (y2-y1)/(x2-x1) (x-x1)
y-2 = (-4-2)/(-3-6) (x-6)
y-2 = -6/-9(x-6)
y-2 = 2/3 (x-6)
y-2 = 2/3x - 4
y = 2/3 x -4+2
y = 2/3 x - 2

Answer 2

M = (y2-y1) / (x2-x1)
m = (2+4) / (6+3) = 6/9 = 2/3

y-y1 = m(x-x1)
y+4 = 2/3 (x+3)
3(y+4) = 2(x+3)
3y+12 = 2x+6
3y = 2x-6