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(6,-8)
penyelesaian:
y-y1=m(x-x1)
y+8=-2/3(x-6)
y+8=-2/3x-4
y+2/3x=-12
m=-2/3
y+8 = -2/3(x-6)
y+8 = -2x/3 + 12/3
3y+24 = -2x+12
2x+3y+12 = 0